A particle of mass 'm' is projected with a velocity $$\upsilon $$ = kV e = (k < 1) from the surface of the earth. (V e = escape velocity) The maximum height above the surface reached by the particle is :

$${{R{k^2}} \over {1 - {k^2}}}$$

The escape velocity of a body on the earth surface is $$11.2 \mathrm{~km} / \mathrm{s}$$. If the same body is projected upward with velocity $$22.4 \mathrm{~km} / \mathrm{s}$$, the velocity of this body at infinite distance from the centre of the earth will be:

$$11.2 \sqrt{3} \mathrm{~km} / \mathrm{s}$$

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NEET Escape Speed And Motion Of Satellites Questions with Answers and Solutions

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NEET Escape Speed And Motion Of Satellites practice

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The escape velocity from the Earth's surface is

v

. The escape velocity from the surface of another planet having a radius four times that of Earth and the same mass density is: i. Calculate the escape velocity from Earth using the formula

v_e = \sqrt{\frac{2GM}{R}}

, where

G

is the gravitational constant,

M

is the mass of the planet, and

R

is the radius of the planet. ii. Given that the radius of the other planet is four times that of Earth, determine the new radius

R'

. iii. Since the mass density is the same, the mass

M'

of the other planet can be expressed in terms of the mass

M

of Earth. iv. Calculate the escape velocity

v'

from the surface of the other planet using the new radius

R'

and mass

M'

. v. Determine the relationship between

v'

and

v

Choose one answer to reveal the solution.

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NEET Escape Speed And Motion Of Satellites practice FAQ

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NEET Escape Speed And Motion Of Satellites practice

What visitors can use on this page

NEET Escape Speed And Motion Of Satellites practice FAQ

Prepare together, not alone

NEET Escape Speed And Motion Of Satellites practice

What visitors can use on this page

NEET Escape Speed And Motion Of Satellites practice FAQ