If \({\rm{\alpha }} = {\rm{co}}{{\rm{s}}^{ - 1}}\left( {\frac{3}{5}} \right),{\rm{\beta }} = {\rm{ta}}{{\rm{n}}^{ - 1}}\left( {\frac{1}{3}} \right)\) , where \(0 then α – β is equal to:

\({\rm{si}}{{\rm{n}}^{ - 1}}\left( {\frac{9}{{5\sqrt {10} }}} \right)\)

The value of \(si{n^{ - 1}}\left( {\frac{{12}}{{13}}} \right) - si{n^{ - 1}}\left( {\frac{3}{5}} \right)\;\) is equal to:

\(\pi - co{s^{ - 1}}\left( {\frac{{63}}{{65}}} \right)\;\)

JEE Main · Quantitative Aptitude

JEE Main Inverse Trigonometry Questions with Answers and Solutions

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JEE Main Inverse Trigonometry practice

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\text{co}{{\text{s}}^{-1}}\left( \frac{2}{3\text{x}} \right)+\text{co}{{\text{s}}^{-1}}\left( \frac{3}{4\text{x}} \right)=\frac{\text{ }\!\!\pi\!\!\text{ }}{2}\left( \text{x}>\frac{3}{4} \right),

then x is equal to:

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JEE Main Inverse Trigonometry practice FAQ

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JEE Main Inverse Trigonometry practice

What visitors can use on this page

JEE Main Inverse Trigonometry practice FAQ

Prepare together, not alone

JEE Main Inverse Trigonometry practice

What visitors can use on this page

JEE Main Inverse Trigonometry practice FAQ